b^2-22b+120=0

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Solution for b^2-22b+120=0 equation:


Simplifying
b2 + -22b + 120 = 0

Reorder the terms:
120 + -22b + b2 = 0

Solving
120 + -22b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(10 + -1b)(12 + -1b) = 0

Subproblem 1

Set the factor '(10 + -1b)' equal to zero and attempt to solve: Simplifying 10 + -1b = 0 Solving 10 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1b = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1b = 0 + -10 -1b = 0 + -10 Combine like terms: 0 + -10 = -10 -1b = -10 Divide each side by '-1'. b = 10 Simplifying b = 10

Subproblem 2

Set the factor '(12 + -1b)' equal to zero and attempt to solve: Simplifying 12 + -1b = 0 Solving 12 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1b = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1b = 0 + -12 -1b = 0 + -12 Combine like terms: 0 + -12 = -12 -1b = -12 Divide each side by '-1'. b = 12 Simplifying b = 12

Solution

b = {10, 12}

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